There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.<
Question
There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.
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Please show all work (don’t show 5+4 = 9 but you get the idea)
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Math
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2022-02-14T02:01:15+00:00
2022-02-14T02:01:15+00:00 2 Answers
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Answers ( )
Answer:
8,9,10
Step-by-step explanation:
Let x-1, x and x+1 be the consecutive integers
(x-1)(x+1) = 5x + 35
x² – 1 – 5x – 35 = 0
x² – 5x – 36 = 0
x² – 9x + 4x – 36= 0
x(x – 9) + 4(x – 9) = 0
(x – 9)(x + 4) = 0
x = 9, -4
Answer:
Step-by-step explanation:
hello :
let this three consecutive integers : x , x+1 , x+2
x(x+2)=35+5(x+1)
x²+2x=35+5x+5
x²-3x-40=0
(x-8)(x+5)=0 …. x+5 ≠ 0 because : x integer
x-8=0 so : x=8
three consecutive integers are : 8 and 9 and 10