## There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.<

Question

There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.

Will give brainliest to best answer

will give thanks and 5 stars rating to good answers!

Please show all work (don’t show 5+4 = 9 but you get the idea)

in progress
0

Math
3 months
2022-02-14T02:01:15+00:00
2022-02-14T02:01:15+00:00 2 Answers
0 views
0
## Answers ( )

Answer:

8,9,10

Step-by-step explanation:

Let x-1, x and x+1 be the consecutive integers

(x-1)(x+1) = 5x + 35

x² – 1 – 5x – 35 = 0

x² – 5x – 36 = 0

x² – 9x + 4x – 36= 0

x(x – 9) + 4(x – 9) = 0

(x – 9)(x + 4) = 0

x = 9, -4

Answer:Step-by-step explanation:hello :

let this three consecutive integers : x , x+1 , x+2

x(x+2)=35+5(x+1)

x²+2x=35+5x+5

x²-3x-40=0

(x-8)(x+5)=0 …. x+5 ≠ 0 because : x integer

x-8=0 so : x=8

three consecutive integers are :

8 and 9 and 10