There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.<

Question

There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find these integers.

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Please show all work (don’t show 5+4 = 9 but you get the idea)

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Vivian 3 months 2022-02-14T02:01:15+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-02-14T02:02:31+00:00

    Answer:

    8,9,10

    Step-by-step explanation:

    Let x-1, x and x+1 be the consecutive integers

    (x-1)(x+1) = 5x + 35

    x² – 1 – 5x – 35 = 0

    x² – 5x – 36 = 0

    x² – 9x + 4x – 36= 0

    x(x – 9) + 4(x – 9) = 0

    (x – 9)(x + 4) = 0

    x = 9, -4

    0
    2022-02-14T02:03:02+00:00

    Answer:

    Step-by-step explanation:

    hello :

    let this three consecutive integers : x  , x+1  , x+2

    x(x+2)=35+5(x+1)

    x²+2x=35+5x+5

    x²-3x-40=0

    (x-8)(x+5)=0   …. x+5 ≠ 0 because : x integer

    x-8=0   so : x=8

    three consecutive integers are : 8 and 9 and 10

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45:7+7-4:2-5:5*4+35:2 =? ( )