This may prove to be somewhat tricky.) Suppose that we have 10 coins, which are weighted so thatwhen flipped theith coin shows heads with pr

Question

This may prove to be somewhat tricky.) Suppose that we have 10 coins, which are weighted so thatwhen flipped theith coin shows heads with probabilityp=i/10 (i= 1, . . . ,10). You randomly pick onecoin, you flip it, and it shows heads.Withoutputting this coin back, you pick a second coin. What is theprobability that the second coin shows heads, given that the first coin showed heads?

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Athena 4 weeks 2021-12-29T01:15:24+00:00 1 Answer 0 views 0

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  1. Ava
    0
    2021-12-29T01:16:55+00:00

    Answer:

    2/10

    Step-by-step explanation:

    Probability of getting head on i’th coin = i/10

    Probability Pr of getting head on 2nd coin (Event A) = 2 / 10

    Probability Pr of getting head on 1st coin (Event B) = 1/10

    Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;

    where A∩B = Pr (A & B) = Pr A X Pr B

    Putting in above formula :

    Pr (A/B) = [(1/10)x(2/10)]  / 1/10

    = 2/10

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