Three numbers have a sum of 68. The second number is 1 less than twice the first. The third number is three times the second. What are the

Question

Three numbers have a sum of 68. The second number is 1 less than twice the first. The third number is three times the second. What are the three numbers?

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Elliana 2 weeks 2022-01-10T21:33:47+00:00 1 Answer 0 views 0

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    2022-01-10T21:35:38+00:00

    Answer:

    First number: 71/7

    Second number: 135/7

    Third number: 270/7

    Step-by-step explanation:

    First number = x

    Second number= 2x-1

    Third number= 2(2x-1)

    x+(2x-1)+2(2x-1)= 68

    3x-1+4x-2=68

    7x-3=68

    7x=71

    x=71/7

    You can check by plugging in the x into the equation.

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45:7+7-4:2-5:5*4+35:2 =? ( )