Triangle 1 has an angle that measures 62° and an angle that measures 14°. Triangle 2 has an angle that measures 14° and an angle that measur

Question

Triangle 1 has an angle that measures 62° and an angle that measures 14°. Triangle 2 has an angle that measures 14° and an angle that measures x°, where x ≠ 62º. Based on the information, Bob claims that triangle 1 and triangle 2 cannot be similar.
2. What value of x, in degrees, will refute Bob’s claim?

in progress 0
Raelynn 1 week 2021-09-11T02:09:34+00:00 1 Answer 0

Answers ( )

    0
    2021-09-11T02:11:19+00:00

    Answer:

    If x ≠ 62° and we want to Refute Bob’s claim that  Δ1 and  Δ2 cannot be similar, the value of x should be:

    x = 104°

    Step-by-step explanation:

    Let’s recall that the interior angles of a triangle add up to 180°, therefore:

    Δ 1 = ∠62° + ∠14° + ∠180° – (62° + 14°)

    Δ 1 = ∠62° + ∠14° + ∠104°

    Then,

    Δ 2 = ∠x° + ∠14° + ∠180° – (x° + 14°)

    Δ 2 = ∠x° + ∠14° + ∠166° – x°

    If x ≠ 62° and we want to Refute Bob’s claim that  Δ1 and  Δ2 cannot be similar, the value of x should be:

    x = 104°

    Replacing with x = 104, in  Δ 2 = ∠x° + ∠14° + ∠166° – x°:

    Δ 2 = ∠104° + ∠14° + ∠166° – 104°

    Δ 2 = ∠104° + ∠14° + ∠62°

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )