TV A frog is sitting on the ground when he is scared by a big dog. His movement is modeled by the equation h = -6t2 + 6t where h
Question
TV
A frog is sitting on the ground when he is scared by a big dog. His movement is modeled by
the equation h = -6t2 + 6t where h is the frog’s height at any given time, t. How many
seconds until the frog is back on the ground?
2 seconds
1.5 seconds
3 seconds
1 second
0.5 seconds
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Math
3 months
2022-02-09T07:08:53+00:00
2022-02-09T07:08:53+00:00 1 Answer
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Answer:
Step-by-step explanation:
Model of the frog jump is
h = -6t² + 6t
When will the frog be on the ground? The frog will be on the ground at h=0
Therefore,
0 = -6t² + 6t
Divide through by 6
0 = -t² + t
0 = t(-t + 1)
So, t = 0 OR. 0 = -t + 1
So, t = 0. OR. t = 1
So, we should note that, at t = 0, was when he wanted to lift of from the ground… So, t = 0 will be discarded
So, at t = 1 is when the frog is back to the ground.
It is like it starts from the ground at the 0 seconds and get backs to the ground at 1 seconds
I hope this helps!!!