TV A frog is sitting on the ground when he is scared by a big dog. His movement is modeled by the equation h = -6t2 + 6t where h

Question

TV
A frog is sitting on the ground when he is scared by a big dog. His movement is modeled by
the equation h = -6t2 + 6t where h is the frog’s height at any given time, t. How many
seconds until the frog is back on the ground?
2 seconds
1.5 seconds
3 seconds
1 second
0.5 seconds

in progress 0
Savannah 3 months 2022-02-09T07:08:53+00:00 1 Answer 0 views 0

Answers ( )

    0
    2022-02-09T07:10:01+00:00

    Answer:

    Step-by-step explanation:

    Model of the frog jump is

    h = -6t² + 6t

    When will the frog be on the ground? The frog will be on the ground at h=0

    Therefore,

    0 = -6t² + 6t

    Divide through by 6

    0 = -t² + t

    0 = t(-t + 1)

    So, t = 0 OR. 0 = -t + 1

    So, t = 0. OR. t = 1

    So, we should note that, at t = 0, was when he wanted to lift of from the ground… So, t = 0 will be discarded

    So, at t = 1 is when the frog is back to the ground.

    It is like it starts from the ground at the 0 seconds and get backs to the ground at 1 seconds

    I hope this helps!!!

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )