Two buses leave towns 268 miles apart at the same time and travel toward each other. One bus travels 10 miles per hour slower than the other

Question

Two buses leave towns 268 miles apart at the same time and travel toward each other. One bus travels 10 miles per hour slower than the other. If they meet in 2 hours, what is the rate of each bus?

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Piper 4 hours 2021-09-10T16:01:06+00:00 2 Answers 0

Answers ( )

    0
    2021-09-10T16:02:06+00:00

    Answer: speed of slower bus is 62 mph.

    Speed of faster bus is 72 mph

    Step-by-step explanation:

    Let x represent the the speed of the slower bus.

    One bus travels 10 miles per hour slower than the other. It means that the speed of the faster bus is (x + 10) mph

    Distance = speed × time

    The 2 buses meet in 2 hours.

    Distance travelled by the slower bus in 2 hours is 2 × x = 2x

    Distance travelled by the faster bus in 2 hours is

    2(x + 10)

    By the time they meet, they would have travelled 268 miles. It means that

    2x + 2(x + 10) = 268

    2x + 2x + 20 = 268

    4x + 20 = 268

    4x = 268 – 20

    4x = 248

    x = 248/4

    x = 62 mph

    Speed of the faster bus is

    x + 10 = 62 + 10 = 72 mph

    0
    2021-09-10T16:03:01+00:00

    Answer:

    Rate of first bus       = 72 mph

    Rate of second bus  = 62 mph

    Step-by-step explanation:

    let first bust travels at x mph

    then,  2nd but will travel at ( x – 10) mph

    distance travelled by first bus in 2 hours = 2x

    distance travelled by 2nd but in 2 hours = 2( x- 10) = 2x – 20

    distance between the two is 268 miles

    so we can write

    2x + 2x – 20 = 268

    4x = 288

    x = 288 / 4 = 72 mph

    rate of first bus = 72 mph

    and second bus = 72 – 10 = 62 mph

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