## Two buses leave towns 268 miles apart at the same time and travel toward each other. One bus travels 10 miles per hour slower than the other

Question

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## Answers ( )

Answer: speed of slower bus is 62 mph.

Speed of faster bus is 72 mph

Step-by-step explanation:

Let x represent the the speed of the slower bus.

One bus travels 10 miles per hour slower than the other. It means that the speed of the faster bus is (x + 10) mph

Distance = speed × time

The 2 buses meet in 2 hours.

Distance travelled by the slower bus in 2 hours is 2 × x = 2x

Distance travelled by the faster bus in 2 hours is

2(x + 10)

By the time they meet, they would have travelled 268 miles. It means that

2x + 2(x + 10) = 268

2x + 2x + 20 = 268

4x + 20 = 268

4x = 268 – 20

4x = 248

x = 248/4

x = 62 mph

Speed of the faster bus is

x + 10 = 62 + 10 = 72 mph

Answer:Rate of first bus =

72 mph

Rate of second bus =

62 mphStep-by-step explanation:let first bust travels at x mph

then, 2nd but will travel at ( x – 10) mph

distance travelled by first bus in 2 hours = 2x

distance travelled by 2nd but in 2 hours = 2( x- 10) = 2x – 20

distance between the two is 268 miles

so we can write

2x + 2x – 20 = 268

4x = 288

x = 288 / 4 = 72 mph

rate of first bus =

72 mph

and second bus = 72 – 10 =

62 mph