Two horses start a race at the same time . Horse A gallops at a steady rate of 32 feet per second and Horse B gallops at a steady rate of 28

Question

Two horses start a race at the same time . Horse A gallops at a steady rate of 32 feet per second and Horse B gallops at a steady rate of 28 per second. After 5seconds , how much farther will horse A have traveled

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Bella 2 months 2021-10-05T15:06:11+00:00 2 Answers 0 views 0

Answers ( )

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    2021-10-05T15:08:08+00:00

    Answer: horse A travelled 20 feet more than horse B

    Step-by-step explanation:

    The two horses start the race at the same time.

    Distance = speed × time

    Horse A gallops at a steady rate of 32 feet per second. This means that the distance that horse A covers in 5 seconds would be

    32 × 5 = 160 feet.

    Horse B gallops at a steady rate of 28 per second. This means that the distance that horse B covers in 5 seconds would be

    28 × 5 = 140 feet

    The difference in distance covered by both horses is

    160 – 140 = 20 feet

    0
    2021-10-05T15:08:08+00:00

    Assuming your question is how much farther has Horse A traveled than Horse B.

    So after 5 seconds, Horse A already traveled 160 feet.

    While Horse B, after 5 seconds traveled 140 feet.

    So the difference is 20 feet.

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