use a graphing calculator to approximate the vertex of the graph of the parabola defined by the following equation. y=x^2+x+6

Question

use a graphing calculator to approximate the vertex of the graph of the parabola defined by the following equation. y=x^2+x+6

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Adeline 3 weeks 2021-09-23T03:28:50+00:00 1 Answer 0

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    2021-09-23T03:30:49+00:00

    Answer:

    (-1/2, 23/4)

    Step-by-step explanation:

    Vertex of graph: -b/2a

    b=1

    a=1

    Therefore, -1/2 is your x-value

    Solve for y: y=1/4-1/2+6

    y=5 3/4 or 23/4

    Therefore your vertex is: (-1/2, 23/4)

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45:7+7-4:2-5:5*4+35:2 =? ( )