Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (rejec

Question

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).

The test statistic in a right-tailed test is z = 0.52

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Kaylee 4 weeks 2021-09-22T11:36:40+00:00 1 Answer 0

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    2021-09-22T11:38:39+00:00

    Answer:

    The P-value is 0.3015 and the conclusion is to reject the null hypothesis.

    Step-by-step explanation:

    We are given the level of significance of 0.05 and the test statistic in a right-tailed test is z = 0.52.

    Now, the decision rule to reject or fail to reject the null hypothesis based on the P-value is given as;

    • If the P-value of the test statistics is less than the level of significance, then we have sufficient evidence to reject our null hypothesis due to which we conclude to reject the null hypothesis.
    • If the P-value of the test statistics is more than the level of significance, then we have insufficient evidence to reject our null hypothesis due to which we fail to reject the null hypothesis.

    SO, P-value of the test statistics is calculated as;

                P-value = P(Z > 0.52) = 1 – P(Z \leq 0.52)

                              = 1 – 0.6985 = 0.3015

    Now, as the P-value of the test statistics is more than the level of significance as 0.3015 > 0.05, so we have sufficient evidence to reject our null hypothesis due to which we conclude to reject the null hypothesis.

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