Using function notation, describe the transformation. x^2+y^2=1 –> (x-7)^2 + (y+4)^2 = 1 PLEASE HELP!!!

Question

Using function notation, describe the transformation. x^2+y^2=1 –> (x-7)^2 + (y+4)^2 = 1

PLEASE HELP!!!

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Iris 2 weeks 2021-09-27T11:16:18+00:00 2 Answers 0

Answers ( )

    0
    2021-09-27T11:17:28+00:00

    Step-by-step explanation:

    Step 1:  Describe the transformation

    The formula of transformation for this equation is (x - k)^2 + (y - b)^2 = 1

    If k or b has a positive sign in the formula, that means that the you move it to the negative direction.  If k or b has a negative sign in the formula, that means that you move it to the positive direction.

    So if we have (x - 7)^2, that means we move the x value to the positive direction 7 units.

    So if we have (y + 4)^2, that means we move the y value to the negative direction 4 units.

    Answer: To the right 7 units and down 4 units.

    0
    2021-09-27T11:18:11+00:00

    Answer:

    f(x – 7) – 4

    Translation: < 7 , -4 >

    Step-by-step explanation:

    x^2+y^2=1

    Centre: (0,0)

    (x-7)^2 + (y+4)^2 = 1

    Centre: (7,-4)

    Translation: < 7 , -4 >

    If the first function is f(x), the transformed function is:

    f(x – 7) – 4

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