Using function notation, describe the transformation. x^2+y^2=1 –> (x-7)^2 + (y+4)^2 = 1 PLEASE HELPPPPP!!!

Question

Using function notation, describe the transformation. x^2+y^2=1 –> (x-7)^2 + (y+4)^2 = 1

PLEASE HELPPPPP!!!

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Lydia 4 weeks 2021-09-27T11:42:20+00:00 2 Answers 0

Answers ( )

    0
    2021-09-27T11:43:21+00:00

    Answer:

    f(x – 7) – 4     (if f(x) is the original function)

    Step-by-step explanation:

    The equation of a circle is: (x-h)^2+(y-k)^2=r^2, where (h, k) is the centre and r is the radius.

    The original function is a circle with centre at (0, 0) and radius 1. The new function is a circle with centre at (7, -4) and radius 1. So it’s simply a translation of the first one.

    In fact, it’s just a translation 7 units right and 4 units down. So the function notation is f(x – 7) – 4, where f(x) is the original function.

    0
    2021-09-27T11:43:54+00:00

    Answer:

    f(x – 7) – 4

    Translation: < 7 , -4 >

    Step-by-step explanation:

    x^2+y^2=1

    Centre: (0,0)

    (x-7)^2 + (y+4)^2 = 1

    Centre: (7,-4)

    Translation: < 7 , -4 >

    If the first function is f(x), the transformed function is:

    f(x – 7) – 4

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