Using the distance formula, d = √(x2 – x1)2 + (y2 – y1)2, what is the distance between point (-5, -2) and point (8, -3) rounded to the neare

Question

Using the distance formula, d = √(x2 – x1)2 + (y2 – y1)2, what is the distance between point (-5, -2) and point (8, -3) rounded to the nearest tenth?

10.3 units

12.6 units

1 unit

13 units

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Amara 1 month 2021-10-17T14:42:02+00:00 1 Answer 0 views 0

Answers ( )

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    2021-10-17T14:43:23+00:00

    Option D: 13 units is the distance between the two points

    Explanation:

    Given that the points are (-5,-2) and (8,-3)

    We need to find the distance between the two points.

    The distance between the two points can be determined using the distance formula,

    d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

    Let us substitute the points (-5,-2) and (8,-3) in the above formula, we get,

    d=\sqrt{(8-(-5))^2+(-3-(-2))^2}

    Simplifying the terms within the bracket, we have,

    d=\sqrt{(8+5)^2+(-3+2)^2}

    Adding the terms within the bracket, we get,

    d=\sqrt{(13)^2+(-1)^2}

    Squaring the terms, we have,

    d=\sqrt{169+1}

    Adding, we get,

    d=\sqrt{170}

    Simplifying, we have,

    d=13.04

    Rounding off to the nearest tenth, we get,

    d=13.0 \ units

    Hence, the distance between the two points is 13 units.

    Therefore, Option D is the correct answer.

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