Using the quadratic formula to solve 5x = 6×2 – 3, what are the values of x? StartFraction 5 plus-or-minus 3 StartRoot 11 EndRoot Over 12 En

Question

Using the quadratic formula to solve 5x = 6×2 – 3, what are the values of x? StartFraction 5 plus-or-minus 3 StartRoot 11 EndRoot Over 12 EndFraction StartFraction 5 plus-or-minus StartRoot 97 EndRoot Over 12 EndFraction StartFraction 5 plus-or-minus StartRoot 47 EndRoot Over 12 EndFraction StartFraction negative 5 plus-or-minus StartRoot 97 EndRoot Over 12 EndFraction

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Josephine 1 month 2021-10-13T19:39:39+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-13T19:40:43+00:00

    Answer:

    The answer is B

    Step-by-step explanation:

    0
    2021-10-13T19:41:03+00:00

    Answer:

    Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?

    5x = 6x^2 – 3

    Subtract 5x from both sides:

    0 = 6x^2 – 5x – 3

    a = 6, b = -5, c = -3

    x = (-b ± √(b^2 – 4ac))/(2a)

    x = (-(-5) ± √((-5)^2 – 4(6)(-3)))/(2(6))

    x = (5 ± √(25 + 72))/12

    x = (5 ± √(97))/12

    Step-by-step explanation:

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45:7+7-4:2-5:5*4+35:2 =? ( )