We are standing on the top of a 128 feet tall building and launch a small object upward. The object’s vertical position, measured in feet, a

Question

We are standing on the top of a 128 feet tall building and launch a small object upward. The object’s vertical position, measured in feet, after t seconds is h ( t ) = − 16 t 2 + 32 t + 128 . What is the highest point that the object reaches?

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Piper 4 weeks 2021-09-19T03:58:38+00:00 1 Answer 0

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    2021-09-19T03:59:38+00:00

    Answer:

    h(t) = -16t^{2} + 32t + 128

    h(t) = 128 feet

    128 =  -16t^{2}  + 32t + 128

    -16t^{2} + 32t + 128 – 128 = 0

    -16t^{2} + 32t  =

    -16t^{2}  = – 32t

    divide through by 16t

      -16t^{2}/ 16t      =    -32t/16t

       t =  2

    t = 2 seconds

    Step-by-step explanation:

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