What are the x-intercepts of the function f(x) = –2×2 – 3x + 20? (–4, 0) and five-halves five-halves and (4, 0) (–5, 0) and (2, 0) (–2, 0)

Question

What are the x-intercepts of the function f(x) = –2×2 – 3x + 20? (–4, 0) and five-halves five-halves and (4, 0) (–5, 0) and (2, 0) (–2, 0) and (5, 0)

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Melody 1 month 2021-10-17T13:46:07+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-17T13:47:13+00:00

    Answer:

    (-4, 0) and (5/2, 0)

    Step-by-step explanation:

    0
    2021-10-17T13:47:57+00:00

    Answer:

    (-4, 0) and (5/2, 0)

    Step-by-step explanation:

    f(x) = –2×2 – 3x + 20

    factor  using the diamond method

    -2*20 = -40

    so  -8 * 5 = -40  and   -8 + 5 = -3  so…

    f(x) = -2x^2 – 8x + 5x  + 20

    f(x) = -2x (x + 4) + 5 *(x + 4)

    f(x) = (-2x + 5)*(x + 4)

    x-intercepts are   x = 5/2  and x =-4

    (-4, 0) and (5/2, 0)

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