What are the values of x in the equation x2 – 6x + 9 = 25? x=-2 or x = 8 x=-1 or x=-11 x = 1 or x = 11 x= 2 or x = –

Question

What are the values of x in the equation x2 – 6x + 9 = 25?
x=-2 or x = 8
x=-1 or x=-11
x = 1 or x = 11
x= 2 or x = -8

in progress 0
Lyla 4 weeks 2021-09-19T16:22:23+00:00 2 Answers 0

Answers ( )

    0
    2021-09-19T16:23:48+00:00

    Answer:

    a

    Step-by-step explanation:

    0
    2021-09-19T16:23:51+00:00

    Answer:

    x= -2 or x= 8

    Step-by-step explanation:

    x^{2} - 6x + 9 = 25

    First step, move 25 to the left side so we can do the Quadratic Formula (or you can factor instead.)

    x^{2} -6x + 9 - 25 = 0

    Next, we know that 9-25 equals -16.

    x^{2} - 6x - 16 = 0

    Now find that what two numbers multiply and get 16: 2×8 4×4 and 16×1.

    Now we do some kind of factoring. The most valuable number must be negative since -6x is negative.

    Let’s explain about factoring in Quadratic a little bit.

    Substitue x²-6x-16 as ax²+bx+c=0

    From (ax+d)(bx+c), if we multiply ax and bx, we get the ax²

    If we multiply ax and c, we get acx and we multiply d and bx, we get dbx. (axc+bdx) = bx

    If we multiply d and c, we get c.

    From the factor lf 16, 2×8 seems to be right since -8+2 equals -6 which matches the equation.

    Then we get.

    (x - 8)(x  + 2) = 0

    Seperate both equations.

    x - 8 = 0 \\ x + 2 = 0

    Find the value of both x.

    x = 8 \\ x =  - 2

    The answer is x = -2, 8

    (The explanation might be weird since I don’t know what they are called in English.)

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