What are the zeros of the function f(x) = x2 + 8x +4, expressed in simplest radical form? x=-4+2/3 x=-41/48 x= -8173

Question

What are the zeros of the function f(x) = x2 + 8x +4, expressed in simplest radical form?
x=-4+2/3
x=-41/48
x= -8173
x= -45473

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Nevaeh 3 weeks 2021-09-25T07:41:08+00:00 1 Answer 0

Answers ( )

    0
    2021-09-25T07:42:10+00:00

    Answer:

    x = – 4 ± 2\sqrt{3}

    Step-by-step explanation:

    Given

    f(x) = x² + 8x + 4

    To find the zeros let f(x) = 0, that is

    x² + 8x + 4 = 0 ( subtract 4 from both sides )

    x² + 8x = – 4

    To solve using the method of completing the square

    add ( half the coefficient of the x- term )² to both sides

    x² + 2(4)x + 16 = – 4 + 16

    (x + 4)² = 12 ( take the square root of both sides )

    x + 4 = ± \sqrt{12} = ± 2\sqrt{3} ( subtract 4 from both sides )

    x = – 4 ± 2\sqrt{3}

    Thus the zeros are

    x = – 4 – 2\sqrt{3} and x = – 4 + 2\sqrt{3}

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