What is an equation of the line that contains the point (3,-1) and is perpendicular to the line whose equation is y=-3x+2

Question

What is an equation of the line that contains the point (3,-1) and is perpendicular to the line whose equation is y=-3x+2

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Savannah 2 months 2021-10-15T03:38:50+00:00 1 Answer 0 views 0

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    2021-10-15T03:40:02+00:00

    Answer:

    Equation of the line: 3y=x+10

    Step-by-step explanation:

    If an equation of a line is perpendicular, its gradient will be such that: m_1 \times m_2 = -1

    Since the gradient /slope of the given equation can be inferred as -3, the gradient of the perpendicular line will be \frac{1}{3}.

    Coordinates of a point on the line are (3,-1)

    (y-y_1) = m(x-x_1)\\\\(y-3) = \frac{1}{3} (x+1)\\\\3(y-3) = (x+1)\\3y -9= x+1\\3y = x+1+9\\3y = x+10

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