what is f(x)=8x^2+4x written in vertex form Question what is f(x)=8x^2+4x written in vertex form in progress 0 Math Alice 3 months 2021-10-18T11:08:09+00:00 2021-10-18T11:08:09+00:00 1 Answer 0 views 0

## Answers ( )

Answer:f(x) = 8 (x + ¼)² − ½

Step-by-step explanation:f(x) = 8x² + 4x

Divide both sides by 8.

1/8 f(x) = x² + 1/2 x

Take half of the second coefficient, square it, then add to both sides.

(½ / 2)² = (1/4)² = 1/16

1/8 f(x) + 1/16 = x² + 1/2 x + 1/6

Factor the perfect square.

1/8 f(x) + 1/16 = (x + 1/4)²

Multiply both sides by 8.

f(x) + 1/2 = 8 (x + 1/4)²

Subtract 1/2 from both sides.

f(x) = 8 (x + 1/4)² − 1/2