what is f(x)=8x^2+4x written in vertex form

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what is f(x)=8x^2+4x written in vertex form

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Alice 1 month 2021-10-18T11:08:09+00:00 1 Answer 0 views 0

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    2021-10-18T11:09:40+00:00

    Answer:

    f(x) = 8 (x + ¼)² − ½

    Step-by-step explanation:

    f(x) = 8x² + 4x

    Divide both sides by 8.

    1/8 f(x) = x² + 1/2 x

    Take half of the second coefficient, square it, then add to both sides.

    (½ / 2)² = (1/4)² = 1/16

    1/8 f(x) + 1/16 = x² + 1/2 x + 1/6

    Factor the perfect square.

    1/8 f(x) + 1/16 = (x + 1/4)²

    Multiply both sides by 8.

    f(x) + 1/2 = 8 (x + 1/4)²

    Subtract 1/2 from both sides.

    f(x) = 8 (x + 1/4)² − 1/2

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