What is the axis of symmetry of h(x)= 5x^2+40x+ 64?

Question

What is the axis of symmetry of h(x)= 5x^2+40x+ 64?

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Alexandra 2 months 2021-10-05T11:21:34+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-05T11:23:18+00:00

    Answer:

    Axis of symmetry is  x = -4

    Step-by-step explanation:

    h(x)= 5x^2+40x+ 64

    Use the formula for axis of symmetry:   x = -b/(2a)

    Here,  a = 5,  b = 40,  c = 64

    so

    x = -40/(2*5) = -40/10 = -4

    Axis of symmetry is  x = -4

    0
    2021-10-05T11:23:19+00:00

    Answer: x=-4

    Step-by-step explanation:

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