What is the approximate area of the octagon? 71 ft2 101 ft2 110 ft2 202 ft2

Question

What is the approximate area of the octagon? 71 ft2 101 ft2 110 ft2 202 ft2

in progress 0
Amara 2 weeks 2021-09-10T15:02:14+00:00 2 Answers 0

Answers ( )

    0
    2021-09-10T15:03:31+00:00

    Answer:

    101

    Step-by-step explanation:

    0
    2021-09-10T15:03:46+00:00

    Answer:

    101   i hope this helps

    Step-by-step explanation:

    Given: A standard octagon has a span of 6 ft and a side length of 4.6 ft.  

    To discover the territory of a normal octagon(A) of side length an is given by :  

    A=2*(1+\sqrt{2})a^{2}

    Given the length of side, a= 4.6 ft  

    Substitute the estimation of a=4.6 ft in the given equation of zone:  

    A=2*(1+\sqrt{2} )*(4.5)^{2}

    or then again  

    A=(2+2\sqrt{2} )*(21.16)

    or then again  

    A=(2+2.828) *(21.16)

    Streamline:  

    A=4.828*21.16=102.16048 ft^{2}

    along these lines, the inexact zone of ordinary octagon is, 101 square ft

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )