What is the approximate value of log 12 if log 2 =0.301, log 3 =0.477, and log 6 = 0.778

Question

What is the approximate value of log 12 if log 2 =0.301, log 3 =0.477, and log 6 = 0.778

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Isabella 12 hours 2021-09-11T10:07:51+00:00 1 Answer 0

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    2021-09-11T10:09:34+00:00

    Answer:1.079

    Step-by-step explanation:

    We know that log a +log b = logab

    Using this rule, we will find log12.

    Log6 + log2= log12

    .778 + .301 = 1.079

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