What is the center and radius of the circle that has the equation (x + 7)^ 2 + (y − 4) ^2 = 49? Explain.

Question

What is the center and radius of the circle that has the equation (x + 7)^ 2 + (y − 4) ^2 = 49? Explain.

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2 weeks 2022-01-08T11:02:02+00:00 2 Answers 0 views 0

Answers ( )

  1. Charlotte
    0
    2022-01-08T11:03:08+00:00

    Answer:

    (- 7, 4 ) and 7

    Step-by-step explanation:

    The equation of a circle in standard form is

    (x – h)² + (y – k)² = r²

    where (h, k) are the coordinates of the centre and r is the radius

    (x + 7)² + (y – 4)² = 49 , that is

    (x – (- 7))² + (y – 4)² = 7² ← is in standard form

    with centre = (h, k) = (- 7, 4) and r = 7

  2. Charlotte
    0
    2022-01-08T11:03:22+00:00

    Step-by-step explanation:

    Center: (−7,4)(-7,4)

    Radius: 7

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45:7+7-4:2-5:5*4+35:2 =? ( )