What is the x-coordinate of the point that divides the directed line segment from J to k into a ratio of 2:5? = – +<

Question

What is the x-coordinate of the point that divides the directed
line segment from J to k into a ratio of 2:5?
=

+
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Anna 2 weeks 2021-09-08T13:46:10+00:00 1 Answer 0

Answers ( )

    0
    2021-09-08T13:47:12+00:00

    The x – coordinate of the point is x=-2

    Explanation:

    Given that the coordinates of the two points J and K are (-6,-2) and (8,-9)

    We need to determine the x – coordinate of the point that divides the directed line segment from J to K into a ratio of 2 : 5

    The value of the x – coordinate can be determined using the formula,

    x=\frac{m}{m+n} (x_2-x_1)^2+x_1

    where m = 2, n = 5 and x_1=-6 and x_2=8 in the above formula, we get,

    x=\frac{2}{2+5} (8+6)+(-6)

    Simplifying, we get,

    x=\frac{2}{7} (14)-6

    Dividing the terms, we get,

    x=2(2)-6

    Multiplying the terms, we have,

    x=4-6

    Subtracting, we get,

    x=-2

    Thus, the x – coordinate of the point is x=-2

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45:7+7-4:2-5:5*4+35:2 =? ( )