What is the equation of a circle with a center at (-4,0) t passes through the point (-2, 1)? x2 + (y + 4)2 = square root 5

Question

What is the equation of a circle with a center at (-4,0)
t passes through the point (-2, 1)?
x2 + (y + 4)2 = square root 5
(x – 1)2 + (y + 2)2 = 5
(x + 4)2 + y2 = 5
(x + 2)2 + (y – 1)2 = square root 5

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Katherine 2 weeks 2022-01-08T15:11:49+00:00 1 Answer 0 views 0

Answers ( )

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    2022-01-08T15:13:12+00:00

    Answer:

    (x+4)^2 + y^2 = 5

    Step-by-step explanation:

    Circle equation: (x-h)^2 + (y-k)^2 = r^2

    We need to find h, k , r^2 to complete the equation.

    (h,k) is center point, in this case is given (-4,0) = (h,k)

    h=-4

    k=0

    Substitute to equation: (x+4)^2+(y-0)^2=r^2

    Use the initial condition: circle passes through the point (-2,1) = (x,y)

    x=-2

    y=1

    Substitute to equation: (-2+4)^2 + (1)^2=r^2

    Solve for r^2 = 5

    Final answer: (x+4)^2 + y^2 = 5

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