What is the equation of a line parallel to y=-2x+10 that contains (6,8)

Question

What is the equation of a line parallel to y=-2x+10 that contains (6,8)

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Eva 1 week 2021-10-05T05:17:35+00:00 1 Answer 0

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    2021-10-05T05:19:31+00:00

    Answer:

    y=-2x+20

    Step-by-step explanation:

    Line is parallel to y=-2x+10,then slope that line is – 2=k.

    A(6,8).. x1=6,y1 =8

    y-y1=k(x-x1)

    y-8=-2(x-6)

    y-8=-2x+12

    y=-2x+12+8

    y=-2x+20

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45:7+7-4:2-5:5*4+35:2 =? ( )