What is the equation of a line parallel to y=-2x+10 that contains (6,8) Question What is the equation of a line parallel to y=-2x+10 that contains (6,8) in progress 0 Math Eva 1 week 2021-10-05T05:17:35+00:00 2021-10-05T05:17:35+00:00 1 Answer 0

## Answers ( )

Answer:

y=-2x+20

Step-by-step explanation:

Line is parallel to y=-2x+10,then slope that line is – 2=k.

A(6,8).. x1=6,y1 =8

y-y1=k(x-x1)

y-8=-2(x-6)

y-8=-2x+12

y=-2x+12+8

y=-2x+20