What is the equation of a line perpendicular to y-12=2x-3 that passes through the point (2, 3)? Question What is the equation of a line perpendicular to y-12=2x-3 that passes through the point (2, 3)? in progress 0 Math Sarah 3 weeks 2021-09-08T08:18:31+00:00 2021-09-08T08:18:31+00:00 1 Answer 0

## Answers ( )

Answer:y = – x + 4

Step-by-step explanation:The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

y – 12 = 2x – 3 ( add 12 to both sides )

y = 2x + 9 ← in slope- intercept form

with slope m = 2

Given a line with slope m then the slope of a line perpendicular to it is

= – = – , thus

y = – x + c ← is the partial equation

To find c substitute (2, 3) into the partial equation

3 = – 1 + c ⇒ c = 3 + 1 = 4

y = – x + 4 ← equation of perpendicular line