What is the equation of the line that passes through the point (-2,3) and that is perpendicular to the line represented by 3x-2y= -2? <

Question

What is the equation of the line that passes through the point (-2,3) and that is perpendicular to the line represented by 3x-2y= -2?

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Jasmine 2 weeks 2021-09-12T17:35:17+00:00 1 Answer 0

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    2021-09-12T17:37:09+00:00

    Answer:

    3y + 2x = 5

    Step-by-step explanation:

    3x-2y = -2

    2y = 3x + 2

    y = (3/2)x + 1

    Slope is 3/2

    Slope of the Perpendicular line is -2/3

    y = (-2/3)x + c

    x = -2 , y = 3

    3 = (-2/3)(-2) + c

    3 = 4/3 + c

    c = 3 – 4/3 = 5/3

    y = (-2/3)x + 5/3

    3y = -2x + 5

    3y + 2x = 5

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45:7+7-4:2-5:5*4+35:2 =? ( )