What is the equation of the line that passes through the points: (1,-2) and (3,-8)

Question

What is the equation of the line that passes through the points: (1,-2) and (3,-8)

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Everleigh 3 weeks 2021-09-26T00:34:29+00:00 2 Answers 0

Answers ( )

  1. Answer:

    y = -3x + 1

    Step-by-step explanation:

    Step 1:  Determine what the values of x1, x2, y1, y2 are

    To find the slope use the formula, m = \frac{y2-y1}{x2-x1}

    (x1, y1) is (1, -2)

    (x2, y2) is (3, -8)

    Step 2:  Plug into the slope formula

    m = \frac{y2-y1}{x2-x1}

    m = \frac{-8 - (-2)}{3-1}

    m = \frac{-8 + 2}{2}

    m = \frac{-6}{2}

    m = -3

    Step 3:  Determine what the values of y1, m, x1 in the point slope form

    (y – y1) = m(x – x1)

    (x1, y1) is (1, -2)

    m = -3

    Step 4:  Plug into the point slope form

    (y – y1) = m(x – x1)

    (y – (-2)) = -3(x – 1)

    y + 2 – 2 = -3x + 3 – 2

    y = -3x + 1

    Answer:  y = -3x + 1

  2. Answer:

    Step-by-step explanation:

    y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} (x-x_{1})\\y+2= \frac {-8+2}{3-1} (x-1)\\y+2=-3(x-1)\\or~y=-3x+3-2\\or~y=-3x+1

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