What is the equation of the line that passes through the points (2, -1) and (6, 1)? o y = 1/2 X-2 y= 2x-5 oy – 2x – 1

Question

What is the equation of the line that passes through the points (2, -1) and (6, 1)?
o y = 1/2 X-2
y= 2x-5
oy – 2x – 1
o y=-2x-3

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Autumn 4 weeks 2021-12-30T20:49:50+00:00 1 Answer 0 views 0

Answers ( )

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    2021-12-30T20:50:54+00:00

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    Answer:

      (a)  y = 1/2x -2

    Step-by-step explanation:

    You can quickly determine that none of the equations with ±2x will work by trying the second point, (6, 1), in them. This only leaves …

      y = 1/2x -2

    __

    Or, you can use the slope formula …

      m = (y2 -y1)/(x2 -x1)

      m = (1 -(-1))/(6 -2) = 2/4 = 1/2

    This tells you the equation will be of the form …

      y = 1/2x +b

    Only one choice matches:

      y = 1/2x -2

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45:7+7-4:2-5:5*4+35:2 =? ( )