what is the equation of the line that passes through the points (-3,0.5) and (3,-0.5)

Question

what is the equation of the line that passes through the points (-3,0.5) and (3,-0.5)

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Rylee 12 hours 2021-09-10T21:41:45+00:00 1 Answer 0

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    2021-09-10T21:43:27+00:00

    Answer:

    y = -1/6x + 0

    Step-by-step explanation:

    Using the equation of line

    y_2 – y_1 / x_2 – x_1 = y – y_1 / x_1

    Using the information we are provided with

    ( -3, 0.5)(3 , -0.5)

    y_1 = 0.5

    x_1 = -3

    x_2 = 3

    y_2 = -0.5

    -0.5 – 0.5 / 3- (-3) = y – 0.5 / x – (-3)

    -0.5 – 0.5 / 3 +3 = y – 0.5 / x + 3

    -1 / 6 = y – 0.5 / x + 3

    Cross multiply

    -1(x + 3) = 6(y – 0.5)

    Open the brackets

    -x – 3 = 6y – 3

    -x – 3 + 3 = 6y

    -x + 0 = 6y

    Divide through by 6 to get y

    Following the eqn y = mx + C

    -x + 0 / 6 = 6y / 6

    y = -x + 0 / 6

    We can separate it

    y = -x / 6 + 0/6

    y = -1/6x + 0

    Therefore, the equation of the line is

    y = -1/6x + 0

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