What is the equation of the quadratic function with a vertex at (2,-25) and an x-intercept at(7,0)

Question

What is the equation of the quadratic function with a vertex at (2,-25) and an x-intercept at(7,0)

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Hailey 2 months 2021-10-17T00:13:48+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-17T00:15:16+00:00

    Answer:

    the answer is d

    Step-by-step explanation:

    0
    2021-10-17T00:15:37+00:00

    The equation of the quadratic function is y=(x-7)(x+3)

    Explanation:

    The vertex form of the quadratic function is given by

    y=a(x-h)^{2}+k

    It is given that the quadratic function has a vertex at (2,-25)

    The vertex is represented by the coordinate (h,k)

    Hence, substituting (h,k)=(2,-25) in the vertex form, we get,

    y=a(x-2)^{2}-25

    Now, substituting the x – intercept (7,0) , we have,

    0=a(7-2)^{2}-25

    0=a(5)^{2}-25

    25=a(25)

     1=a

    Thus, the value of a is 1.

    Hence, substituting a=1, (h,k)=(2,-25) in the vertex form y=a(x-h)^{2}+k , we get,

    y=1(x-2)^{2}-25

    y=(x-2)^{2}-25

    y=x^2-2x+4-25

    y=x^2-2x-21

    y=(x-7)(x+3)

    Thus, the equation of the quadratic function is y=(x-7)(x+3)

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45:7+7-4:2-5:5*4+35:2 =? ( )