What is the greatest common factor of: 16 m 2 n 2 − 12 m n 2 + 20 m 2 n ?

Question

What is the greatest common factor of: 16 m 2 n 2 − 12 m n 2 + 20 m 2 n ?

in progress 0
Adeline 3 months 2022-02-17T19:35:50+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-02-17T19:37:02+00:00

    GCF would be 4mn

    Hope this help!

    0
    2022-02-17T19:37:41+00:00

    Answer:

    The GCF is 4mn.

    Step-by-step explanation:

    16 m^2*n^2 − 12 m*n^2 + 20 m^2*n is the correct way to write this expression.

    Note that there are 3 terms, and that 4 is common to all three coefficients.  Therefore,

    16 m^2*n^2 − 12 m*n^2 + 20 m^2*n  =  4(4 m^2*n^2 − 3 m*n^2 + 5 m^2*n).

    Also note that m and n are common to all three terms, but only in the first power:  m^1 and n^1.

    Thus, 4(4 m^2*n^2 − 3 m*n^2 + 5 m^2*n)  =  (4mn)(m*n – 3n + 5 m)

    The GCF is 4mn.

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )