What is the greatest common factor of: 16 m 2 n 2 − 12 m n 2 + 20 m 2 n ? Question What is the greatest common factor of: 16 m 2 n 2 − 12 m n 2 + 20 m 2 n ? in progress 0 Math Adeline 3 months 2022-02-17T19:35:50+00:00 2022-02-17T19:35:50+00:00 2 Answers 0 views 0

## Answers ( )

GCF would be 4mn

Hope this help!

Answer:The GCF is 4mn.Step-by-step explanation:16 m^2*n^2 − 12 m*n^2 + 20 m^2*n is the correct way to write this expression.

Note that there are 3 terms, and that 4 is common to all three coefficients. Therefore,

16 m^2*n^2 − 12 m*n^2 + 20 m^2*n = 4(4 m^2*n^2 − 3 m*n^2 + 5 m^2*n).

Also note that m and n are common to all three terms, but only in the first power: m^1 and n^1.

Thus, 4(4 m^2*n^2 − 3 m*n^2 + 5 m^2*n) = (4mn)(m*n – 3n + 5 m)

The GCF is 4mn.