What is the perimeter of ABC with vertices A(-2,9), B(7,-3), and C(-2,-3) and in the coordinate plain? A. 21 units B. 15 units

Question

What is the perimeter of ABC with vertices A(-2,9), B(7,-3), and C(-2,-3) and in the coordinate plain?
A. 21 units
B. 15 units
C. 34 units
D. 36 units

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Delilah 1 month 2021-10-20T16:28:25+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-20T16:29:38+00:00

    Answer:

    36units

    Step-by-step explanation: A – C = ( -2, 9) – (- 2 -3) 

    = ( 0, 12) 

    AC = 12 

    B – C = (7 – 3) – ( – 2 -3) 

    = (9, 0) 

    BC = 9 

    ABC is a right -angled triangle with AC as the hypotenuse 

    AC = sqrt( 9^2 + 12^2) 

    = sqrt(81 + 144) 

    = srqt(225) 

    = 15 

    Perimeter = 12 + 9 + 15 

    = 36 units 

     So the answer is 36 units

    0
    2021-10-20T16:29:52+00:00

    Answer:

    Step-by-step explanation:

    A – C = ( -2, 9) – (- 2 -3) 

    = ( 0, 12) 

    AC = 12 

    B – C = (7 – 3) – ( – 2 -3) 

    = (9, 0) 

    BC = 9 

    ABC is a right -angled triangle with AC as the hypotenuse 

    AC = sqrt( 9^2 + 12^2) 

    = sqrt(81 + 144) 

    = srqt(225) 

    = 15 

    Perimeter = 12 + 9 + 15 

    = 36 units 

     So the answer is 36 units

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