## What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x Over x sq

Question

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## Answers ( )

Answer:

[x(x – 1)(x – 4)]/(2(x + 4))

Step-by-step explanation:

We want to find;

[(x² – 16)/(2x + 8)] * [(x³ – 2x² + x)/(x² + 3x – 4)]

Now,

x² – 16 can be factorized as;

(x + 4)(x – 4)

Also, 2x + 8 can be factorized as;

2(x + 4)

Also, (x³ – 2x² + x) can factorized as;

x[x² – 2x + 1] = x[(x – 1)(x – 1)]

Also,(x² + 3x – 4) can be factorized out as; (x – 1)(x + 4)

So plugging in these factorized forms into the equation in the question, we have;

[(x + 4)(x – 4)/(2(x + 4))] * [x[(x – 1)(x – 1)] /((x – 1)(x + 4))

This gives;

((x – 4)/2) * x(x – 1)/(x +4)

This gives;

[x(x – 1)(x – 4)]/(2(x + 4))

Answer:[x(x – 1)(x – 4)]/(2(x + 4))

Step-by-step explanation:its A on edg

StartFraction x (x minus 4) (x minus 1) Over 2 (x + 4) EndFraction