What is the range of the function f(x)=sin(2x)-2

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What is the range of the function f(x)=sin(2x)-2

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Amelia 2 weeks 2021-09-07T01:01:21+00:00 1 Answer 0

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    2021-09-07T01:02:42+00:00

    Answer:

    The range of the function f(x)=sin(2x)-2 is given as:

     -3\le \:f\left(x\right)\le \:-1

    Step-by-step explanation:

    To find the range of the function, we can use the graphical approach or the algebraic approach. Now, when the function is having the sine or the cosine terms, then we will use the maximum and the minimum values of these trigonometric ratios, which is 1 and -1 respectively.

    So for the given function , we will find the range as follows.

    We know that:

    -1\le \sin \left(2x\right)\le \:1

    so now subtracting 2, we have:

    -3\le \sin \left(2x\right)-2\le \:-1

    and thus finally we have the range as:

    -3\le \:f\left(x\right)\le \:-1

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45:7+7-4:2-5:5*4+35:2 =? ( )