What is the solution to this system of equations? 4x+6y=7 3x – 2y = -12 Multiply each equation by a number that pro

Question

What is the solution to this system of equations?
4x+6y=7
3x – 2y = -12
Multiply each equation by a number that produces opposite
coefficients for x or y.
The solution is

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Ximena 2 weeks 2021-10-06T20:40:38+00:00 1 Answer 0

Answers ( )

    0
    2021-10-06T20:42:12+00:00

    The solution is x = \frac{-29}{13}, y = \frac{69}{26}

    Solution:

    Given system of equations are:

    4x + 6y = 7 ——— eqn 1

    3x – 2y = -12 ——– eqn 2

    Let us solve the system of equations by elimination method

    Multiply eqn 2 by 3

    9x – 6y = -36 —– eqn 3

    Add eqn 1 and eqn 3

    4x + 6y = 7

    9x – 6y = -36

    ( + ) ————–

    13x = -29

    x = \frac{-29}{13}

    Substitute x = \frac{-29}{13} in eqn 1

    4( \frac{-29}{13}) + 6y = 7\\\\6y = 7 + \frac{4 \times 29}{13}\\\\6y = \frac{207}{13}\\\\y = \frac{69}{26}

    Thus the solution is x = \frac{-29}{13}, y = \frac{69}{26}

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45:7+7-4:2-5:5*4+35:2 =? ( )