What is the sum of a 6-term geometric sequined if the first term is 22 and the last term is 1299078

Question

What is the sum of a 6-term geometric sequined if the first term is 22 and the last term is 1299078

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Luna 2 months 2021-10-14T21:34:04+00:00 1 Answer 0 views 0

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    2021-10-14T21:35:55+00:00

    Answer:

    1461460

    Step-by-step explanation:

    From the question given, we obtained the following data:

    a = 22

    Last term = T6 = 1299078

    Let us find the common ratio(r)

    Tn = ar^(n-1)

    T6 = ar^5

    1299078 = 22r^5

    Divide both side by 22

    r^5 = 1299078/22

    r^5 = 59049

    Take the fifth root of both side

    r = 5√ 59049

    r = 9

    Now we can find the sum of the 6th term as follows

    Sn = a[(r^n) — 1] / (r —1)

    S6 = 22[(9^6) — 1] / 9—1

    S6 = 22[(9^6) — 1] / 9—1

    S6 = 22[531441 — 1] / 8

    S6 = 22[531440] /8

    S6 = 22 x 66430

    S6 = 1461460

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45:7+7-4:2-5:5*4+35:2 =? ( )