What’s the distance between point A (32,15) and point B (32,29

Question

What’s the distance between point A (32,15) and point B (32,29

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Ximena 16 hours 2021-10-12T11:57:19+00:00 2 Answers 0

Answers ( )

    0
    2021-10-12T11:58:39+00:00

    Answer:

     d = \sqrt{(32-32)^2 +(15-29)^2} = \sqrt{196}= 14

    So then we can conclude that the smallest distance between the point A (32,15) and the point B(32,39) is 14

    Step-by-step explanation:

    When we have a two points on a dimensional space A and B we can find the distance between the two points with the following formula:

     d= \sqrt{(x_A -x_B)^2 +(y_A -y_B)^2}

    Where (x_A,y_A) represent the coordinates for the point A and (x_B,y_B) represent the coordinates for the point B. And we know that the coordinates are :

    A= (32,15) and B= (32,29)

    And replacing in the formula for the distance we got:

     d = \sqrt{(32-32)^2 +(15-29)^2} = \sqrt{196}= 14

    So then we can conclude that the smallest distance between the point A (32,15) and the point B(32,39) is 14

    0
    2021-10-12T11:58:50+00:00

    Answer:

      14 units

    Step-by-step explanation:

    Both points lie on the vertical line x=32, so the distance between them is the difference of their y-coordinates:

      29 -15 = 14 . . . . units

    The two points are 14 units apart.

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