What values of b satisfy 3(2b + 3)2 = 36? b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFract

Question

What values of b satisfy 3(2b + 3)2 = 36?

b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFraction negative 3 minus 2 StartRoot 3 EndRoot Over 2 EndFraction
b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFraction negative 3 minus 2 StartRoot 3 EndRoot Over 2 EndFraction
b = StartFraction 3 Over 2 EndFraction and StartFraction negative 9 Over 2 EndFraction
b = Start Fraction 9 Over 2 EndFraction and StartFraction negative 3 Over 2 EndFraction

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Evelyn 1 month 2021-10-18T14:16:13+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-18T14:17:47+00:00

    Answer:

    The answer is A. I just took the test! Thank you

    Step-by-step explanation:

    0
    2021-10-18T14:17:49+00:00

    Answer: b=-3+2√3/2

    -3-2√3/2

    Step-by-step explanation: it’s A on edg

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45:7+7-4:2-5:5*4+35:2 =? ( )