## What values of b satisfy 3(2b + 3)2 = 36? b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFract

Question

What values of b satisfy 3(2b + 3)2 = 36?

b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFraction negative 3 minus 2 StartRoot 3 EndRoot Over 2 EndFraction

b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFraction negative 3 minus 2 StartRoot 3 EndRoot Over 2 EndFraction

b = StartFraction 3 Over 2 EndFraction and StartFraction negative 9 Over 2 EndFraction

b = Start Fraction 9 Over 2 EndFraction and StartFraction negative 3 Over 2 EndFraction

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2021-10-18T14:16:13+00:00
2021-10-18T14:16:13+00:00 2 Answers
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## Answers ( )

Answer:The answer is A. I just took the test! Thank you

Step-by-step explanation:Answer: b=-3+2√3/2-3-2√3/2Step-by-step explanation: it’s A on edg