When playing American​ roulette, the croupier​ (attendant) spins a marble that lands in one of the 38 slots in a revolving turntable. The sl

Question

When playing American​ roulette, the croupier​ (attendant) spins a marble that lands in one of the 38 slots in a revolving turntable. The slots are numbered 1 to​ 36, with two additional slots labeled 0 and 00 that are painted green. Consider the numbers 0 and 00 as neither even nor odd. Half the remaining slots are colored red and half are black. Assume a single spin of the roulette wheel is made. Find the probability of the marble landing on a 00 or even slot. The total number of outcomes is and the number of outcomes in the event is

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Cora 1 week 2021-10-08T10:55:42+00:00 2 Answers 0

Answers ( )

    0
    2021-10-08T10:57:01+00:00

    Answer:

    -0.21

    Step-by-step explanation:

    Firstly the probability for odd or 00 = (18+1)/38 = 0.5

    Therefore we can calculate our expected value as follows :

    14 * win probability – 13 * lose probability

    =14 * (18/38) – 13*(20/38)

    Hence our Answer is = -0.21

    0
    2021-10-08T10:57:35+00:00

    Answer:

    Check the explanation

    Step-by-step explanation:

    1) probability for odd or 00 = (18+1)/38 = 0.5

    2) expected value can be calculated as follows :

    14 * win probability – 13 * lose probability

    =14 * (18/38) – 13*(20/38)

    = -0.21

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45:7+7-4:2-5:5*4+35:2 =? ( )