When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were screened an

Question

When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were screened and 6 were arrested for dri vi ng while intoxicated. Based on those​ results, we can estimate that P(I) = 0.00589​, where W denotes the event of screening a driver and getting someone who is intoxicated. What does P(I¯) ​denote, and what is its​ value?

in progress 0
Isabelle 2 months 2021-10-09T06:17:11+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-09T06:18:54+00:00

    Answer:

    The probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

    Step-by-step explanation:

    As the event is indicated as I for the drivers who are intoxicated, the value of I¯ is for the drivers who are not intoxicated. Its value is calculated as follows

    P(I¯)=1-P(I)

    P(I¯)=1-0.00589

    P(I¯)=0.99411

    So the probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )