## When working with inequalities what do you do when its x squared > 16 and vice versa does the sign flip.

Question

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## Answers ( )

No it doesn’t flip. You split into two possible cases with two separate inequalities.

x^2 > 16

| x | > 4

And since now you are working with an absolute value, you split into 2 possible cases.

if x >= 0: then x > 4

if x < 0: then -x > 4

x < -4

FOR THE FIRST:

x ∈ (4, + ∞)

FOR THE SECOND:

x ∈ (-∞, -4)

Their UNITY is: x ∈ (-∞, -4) U (4, +∞)

And that’s how you go about solving these. Hope I helped! 🙂

Answer:Step-by-step explanation:The interval notation will be:

The contrary,

is