Which compound inequality is equivalent to |ax-b|>c for all real numbers a, b, and c, where c>0

Question

Which compound inequality is equivalent to |ax-b|>c for all real numbers a, b, and c, where c>0

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Josie 2 weeks 2021-09-27T06:03:09+00:00 2 Answers 0

Answers ( )

    0
    2021-09-27T06:04:09+00:00

    Answer:

    D. ax-b<-c or ax-b>c is the correct answer.

    Step-by-step explanation:

    0
    2021-09-27T06:05:04+00:00

    Answer:

    D

    Step-by-step explanation:

    Keywords

    compound inequality, absolute value, equivalent

    we have

    we know that

    To find the compound inequality  calculate the two solutions of the absolute value

    First solution (case positive)

    ——-> inequality A

    Second solution (case negative)

    ——-> inequality B

    Multiply by  all expression

    therefore

    is equivalent to

    and  

    The answer is

    The equivalent compound inequality is

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45:7+7-4:2-5:5*4+35:2 =? ( )