Which expression correctly shows 2x^5y−2x^2y factored completely over the integers? A.−2x^2y(x+1)(x^2−x+1) B.2xy(x−1

Question

Which expression correctly shows 2x^5y−2x^2y factored completely over the integers?

A.−2x^2y(x+1)(x^2−x+1)

B.2xy(x−1)(x^2+x+1)

C.2x^2(x−y)(x+y)

D.2x^2y(x−1)(x^2+x+1)

E.2x^2(x−y)(x^2+xy+y^2)

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Luna 2 weeks 2021-09-10T04:20:09+00:00 1 Answer 0

Answers ( )

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    2021-09-10T04:22:01+00:00

    Answer:

    Option D, 2x^2y(x – 1)(x^2 + x + 1)

    Step-by-step explanation:

    Step 1:  Factor

    2x^5y – 2x^2y

    2x^2y(x^3 – 1)

    2x^2y(x – 1)(x^2 + x + 1)

    Answer:  Option D, 2x^2y(x – 1)(x^2 + x + 1)

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45:7+7-4:2-5:5*4+35:2 =? ( )