Which is 5logx+6log(x + 7) written as a single logarithm?

Question

Which is 5logx+6log(x + 7) written as a single logarithm?

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Autumn 3 months 2022-02-05T13:00:05+00:00 2 Answers 0 views 0

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    0
    2022-02-05T13:01:18+00:00

    Answer: log(x^5(x+7)^6)

    Hope that helps! (:

    0
    2022-02-05T13:01:55+00:00

    [tex]\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 5\log(x)+6\log(x+7)\implies \log(x^5)+\log\left[ \left( x+7 \right)^6 \right] \implies \log\left[ x^5\left( x+7 \right)^6 \right][/tex]

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45:7+7-4:2-5:5*4+35:2 =? ( )