Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)? a. -12(7-6) = (x+5) C (x+5)2 =-12(y-6) b. (+ 5)

Question

Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)?
a. -12(7-6) = (x+5)
C (x+5)2 =-12(y-6)
b. (+ 5)² = -30(7-6)
d. (x+5)2 = -12(7-6)
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Hailey 3 hours 2021-10-12T21:45:36+00:00 2 Answers 0

Answers ( )

    0
    2021-10-12T21:46:41+00:00

    Answer:

    Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)?

    Focus and Vertex are both on x = –5, so that’s the Axis of Symmetry.

    Distance from Vertex to Focus is p = 3-6 = –3.

    4p(y-k) = (x-h)^2

    4(–3)(y–6) = (x-(-5))^2

    –12(y–6) = (x+5)^2

    y = (–1/12)(x+5)^2 + 6 <== Answer

    Distance from Vertex to Directrix is –p = 3.

    Directrix is y = 6+3 = 9.

    Step-by-step explanation:

    0
    2021-10-12T21:47:34+00:00

    Answer: On edg its C: (x+5)^2 = -12(y-6)

    Step-by-step explanation:

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