Which of the following are solutions to the equation below? Check all that apply. 2×2 – 4x – 3 = x

Question

Which of the following are solutions to the equation below?

Check all that apply.

2×2 – 4x – 3 = x

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Faith 1 week 2021-09-15T00:20:08+00:00 2 Answers 0

Answers ( )

    0
    2021-09-15T00:21:08+00:00

    Answer:

    \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                      x=3,\:x=-\frac{1}{2}

    Step-by-step explanation:

    considering the equation

    2x^2\:-\:4x\:-\:3\:=\:x

    solving

    2x^2\:-\:4x\:-\:3\:=\:x

    2x^2-4x-3-x=x-x

    2x^2-5x-3=0

    \mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

    x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

    \mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

    solving

    x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

    x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

    x=\frac{5+\sqrt{49}}{2\cdot \:2}

    x=\frac{5+7}{4}

    x=3

    also solving

    x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

    x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

    x=\frac{5-\sqrt{49}}{4}

    x=-\frac{2}{4}

    x=-\frac{1}{2}

    Therefore,

                     \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                      x=3,\:x=-\frac{1}{2}

    0
    2021-09-15T00:21:47+00:00

    Answer:

    -1/2

    Step-by-step explanation:

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45:7+7-4:2-5:5*4+35:2 =? ( )