Which of the following could be the equation for a parabola that opens to the left with vertex (5, -12)? O A. x = (y-5)2 –

Question

Which of the following could be the equation for a parabola that opens to the
left with vertex (5, -12)?
O
A. x = (y-5)2 – 12
O
B. y = (x+12)2 +5
O
C. y = (x-5)2 – 12
O D. x=-(y+12)2 +5

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Jade 3 weeks 2021-09-25T21:53:26+00:00 1 Answer 0

Answers ( )

    0
    2021-09-25T21:55:07+00:00

    Answer:

    D. x=-(y+12)^2+5

    Step-by-step explanation:

    A parabola that opens to the left has the equation

    (y-y_0)^2=-2p(x-x_0),

    where (x_0,y_0) is the vertex.

    If the vertex of the parabola is at the point (5,-12), then its equation is

    (y-(-12))^2=-2p(x-5)\\ \\(y+12)^2=-2p(x-5)

    When p=\frac{1}{2}, the equation is

    (y+12)^2=-(x-5)\\ \\(y+12)^2=-x+5\\ \\x=-(y+12)^2+5

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45:7+7-4:2-5:5*4+35:2 =? ( )