## Which shows how to find the value of this expression when x = negative 2 and y = 5? (3 x cubed y Superscript negative 2 Baseline) squared

Question

Which shows how to find the value of this expression when x = negative 2 and y = 5? (3 x cubed y Superscript negative 2 Baseline) squared

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3 months 2022-02-19T10:53:00+00:00 2 Answers 0 views 0

$$(3x^3y^{-2})^2$$ =  $$\frac{576}{625}$$

Step-by-step explanation:

Given:

$$x=-2$$

$$y=5$$

To evaluate:

$$(3x^3y^{-2})^2$$

Solution:

Applying property of exponents to simplify the expression.

Property: $$(a^b)^c= a^{bc}$$

So, we have: $$(3x^3y^{-2})^2$$

⇒ $$3^2x^6y^{-4}$$

⇒ $$9x^6y^{-4}$$

Property : $$a^{-b}=\frac{1}{a^b}$$

⇒ $$\frac{9x^6}{y^4}$$

Now, plugging in values of $$x$$ and $$y$$.

⇒ $$\frac{9(-2)^6}{5^4}$$

⇒ $$\frac{9\times 64}{625}$$

⇒ $$\frac{576}{625}$$     (Answer)

2. A) 3^2(-2)^6/5^4

I just took the quiz on edge