Which shows how to find the value of this expression when x = negative 2 and y = 5? (3 x cubed y Superscript negative 2 Baseline) squared

Question

Which shows how to find the value of this expression when x = negative 2 and y = 5? (3 x cubed y Superscript negative 2 Baseline) squared

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Anna 3 months 2022-02-19T10:53:00+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-02-19T10:54:43+00:00

    Answer:

    [tex](3x^3y^{-2})^2[/tex] =  [tex]\frac{576}{625}[/tex]

    Step-by-step explanation:

    Given:

    [tex]x=-2[/tex]

    [tex]y=5[/tex]

    To evaluate:

    [tex](3x^3y^{-2})^2[/tex]

    Solution:

    Applying property of exponents to simplify the expression.

    Property: [tex](a^b)^c= a^{bc}[/tex]

    So, we have: [tex](3x^3y^{-2})^2[/tex]

    ⇒ [tex]3^2x^6y^{-4}[/tex]

    ⇒ [tex]9x^6y^{-4}[/tex]

    Property : [tex]a^{-b}=\frac{1}{a^b}[/tex]

    ⇒ [tex]\frac{9x^6}{y^4}[/tex]

    Now, plugging in values of [tex]x[/tex] and [tex]y[/tex].

    ⇒ [tex]\frac{9(-2)^6}{5^4}[/tex]

    ⇒ [tex]\frac{9\times 64}{625}[/tex]

    ⇒ [tex]\frac{576}{625}[/tex]     (Answer)

    0
    2022-02-19T10:54:49+00:00

    A) 3^2(-2)^6/5^4

    I just took the quiz on edge

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45:7+7-4:2-5:5*4+35:2 =? ( )